设f(x)=x-1/(x+1),则f(x)+f(1/x)=?

设f(x)=1-x,(x 设函数f(x)满足f(x)+2f(1/x)=x,求f(x) 设f(x)+2f(1/x)=2x+1,则f(x)= 设f(x)=x(x+1)(x+2).(x+100),则f '(0)= 设函数f(x)满足f(x)+2f(1/x)=2x+1,则f(x)= 设函数f(x)=log2(-x),g(x)=x+1,F(x)={g(x),f(x)大于等于g(x);f(x),f(x)小 设函数f(x)=x-[x],x≥0,f(x+1),x 设f(x)满足f(x)+f(x-1/x)=x求f(x)的解析式 设函数f(x)=1+f(1/x)log2 x,则f(2)=? 设f(x-1)=x(x-1),则f(x)=( )参考答案f(x-1)=x(x-1)=[(x-1)+1] (x-1)这里[ 设f(x)=ln√x,x>=1,y=f(f(x)) 设2f(x)cos x=d/dx [f(x)]²,f(0)=1,则f(x)=