微积分的题,希望可以提供过程~
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/11/18 12:53:32
微积分的题,希望可以提供过程~
(a)
h'(x) = 5f'(x) - 4g'(x)
f'(2) = 5f'(2) - 4g'(2) = =5(-4) - 4*1 = -24
(b)
h'(x) = f'(x)g(x) + f(x)g'(x)
= -4*2 -5*1 = -13
(c)
h'(x) = [f'(x)g(x) - f(x)g'(x)]/g²(x)
= [(-4)*2 - (-5)*1]/2² = -3/4
(d)
h'(x) = [g'(x)(1 + f(x)) - g(x)(1 + f(x))']/[1 + f(x)]² = [g'(x)(1 + f(x)) - g(x)f'(x)]/[1 + f(x)]²
= [1*(1 -5) -2*4]/(1 - 5)²
= -3/4
再问: D答案错了。可以再算一下吗?
再答: h'(x) = [g'(x)(1 + f(x)) - g(x)(1 + f(x))']/[1 + f(x)]² = [g'(x)(1 + f(x)) - g(x)f'(x)]/[1 + f(x)]² = [1*(1 -5) -2*(-4)]/(1 - 5)² = 1/4 漏了个负号
h'(x) = 5f'(x) - 4g'(x)
f'(2) = 5f'(2) - 4g'(2) = =5(-4) - 4*1 = -24
(b)
h'(x) = f'(x)g(x) + f(x)g'(x)
= -4*2 -5*1 = -13
(c)
h'(x) = [f'(x)g(x) - f(x)g'(x)]/g²(x)
= [(-4)*2 - (-5)*1]/2² = -3/4
(d)
h'(x) = [g'(x)(1 + f(x)) - g(x)(1 + f(x))']/[1 + f(x)]² = [g'(x)(1 + f(x)) - g(x)f'(x)]/[1 + f(x)]²
= [1*(1 -5) -2*4]/(1 - 5)²
= -3/4
再问: D答案错了。可以再算一下吗?
再答: h'(x) = [g'(x)(1 + f(x)) - g(x)(1 + f(x))']/[1 + f(x)]² = [g'(x)(1 + f(x)) - g(x)f'(x)]/[1 + f(x)]² = [1*(1 -5) -2*(-4)]/(1 - 5)² = 1/4 漏了个负号