10b + 771.04m = 1745.4
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/11/18 04:18:59
10b + 771.04m = 1745.4
771.04b + 56048.4m= 135169.22
求:m ,b
771.04b + 56048.4m= 135169.22
求:m ,b
10b+771.04m=1745.4
10b=1745.4-771.04m
b=1745.4-771.04m/10
b=174.54-77.104m
771.04b + 56048.4m= 135169.22
771.04*(174.54-77.104m)+56048.4m= 135169.22
134577.3216-59450.26816m+56048.4m= 135169.22
-3401.86816m=-591.8984
m=0.173992
10b+771.04m=1745.4
10b+771.04*0.173992=1745.4
10b=1611.2452083
b=161.12452083
10b=1745.4-771.04m
b=1745.4-771.04m/10
b=174.54-77.104m
771.04b + 56048.4m= 135169.22
771.04*(174.54-77.104m)+56048.4m= 135169.22
134577.3216-59450.26816m+56048.4m= 135169.22
-3401.86816m=-591.8984
m=0.173992
10b+771.04m=1745.4
10b+771.04*0.173992=1745.4
10b=1611.2452083
b=161.12452083
a(-2,4)b(1,m) a*b=-10 求m等于多少
若5a∧3|m|+1-(m+2)b-10是七次二项式,求m+m=?
已知A=-10m² +3m+3mn,B=-10m²-5m+3mn,试着比较A与B的大小
因式分解12:m²-3m+2=(m+a)(m+b),a=( ),b=( )
已知a^2+9b^2+6a+10=0,求代数式(6a^m+2 b^n+2-4a^m+1 b^n+1+2a^m b^m)除
已知2^m=a,32^n=b,m,n为正整数,求2^(3m+10n)
1.b²×b的m次方+b的³×b的m+1次方=?
main() { int i,mum,m int b[8]={3,5,6,10,0,123.100.-9}} ; m=b
方程1/2m+1/3m=5-1/6m的解是( ) A.m=5. B.m=10 C.m=15. D.m=30
已知a^2+9b^2+6a-6b+10=0,求代数式(6a^m+2 b^n+2-4a^m+1 b^n+1+2a^m b^
(12a^2m+1b^m+3-20a^m+1b^2m+4)/4a^m+1b^m+1=( )
已知A=M-N次根号M+N+10是M+N+10的算术平方根,B=M-2N+3次根号4M+6N-1的立方根求B-A的立方根