(1)、x² 2x+2 x²+2x x+1_________ * __________ - ____
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(1)、
x² 2x+2 x²+2x x+1
_________ * __________ - ________ *______
4x²-4x x³ 3x²-3 x
(2)化简求值
已知x=4分之7,求(x- x分之4)/(x-5加上x分之6)的值.
第(1)题是:4x²-4x 分之x²乘以x³分之2x+2 减去3x²-3分之x²+2x 乘以 x分之x+1
x² 2x+2 x²+2x x+1
_________ * __________ - ________ *______
4x²-4x x³ 3x²-3 x
(2)化简求值
已知x=4分之7,求(x- x分之4)/(x-5加上x分之6)的值.
第(1)题是:4x²-4x 分之x²乘以x³分之2x+2 减去3x²-3分之x²+2x 乘以 x分之x+1
原式=[x^2/4x(x-1)]*[2(x+1)/x^3]-[x(x+2)/3(x+1)(x-1)]*[(x+1)/x]
=(x+1)/2x^2(x-1)-(x+2)/3(x-1)
=(3x+3-2x^3-4x^2)/6x^2(x-1)
=-(x-1)(2x^2+6x+3)/6x^2(x-1)
=-(2x^2+6x+3)/6x^2
原式=[(x^2-4)/x]/[(x^2-5x+6)/x]
=(x+2)(x-2)/(x-2)(x-3)
=(x+2)/(x-3)
=(7/4+2)/(7/4-3)
=-3
=(x+1)/2x^2(x-1)-(x+2)/3(x-1)
=(3x+3-2x^3-4x^2)/6x^2(x-1)
=-(x-1)(2x^2+6x+3)/6x^2(x-1)
=-(2x^2+6x+3)/6x^2
原式=[(x^2-4)/x]/[(x^2-5x+6)/x]
=(x+2)(x-2)/(x-2)(x-3)
=(x+2)/(x-3)
=(7/4+2)/(7/4-3)
=-3
2(x²-1²)
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