log5[log2(log9/log3)]=?

1.log2 3*log3 4*log4 5*log5 2 2.(log4 3+log8 3)8(log3 2+log9 (log2)和(log3)变成(log5) log2(a)=log3(b)=log5(c) 若log2(x)=log3(y)=log5(z) log2^25*log3^2倍根号2*log5^9= log2^5*log3^2倍根号2*log5^9= (log4 3+log8 3)(log3 5+log9 5)(log5 2+log25 2)= log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=? log2 25*log3 4 *log5 9 化简log2[log3(log5 125)]…… 我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log 计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15