已知F(x)=eX—e-X,g(x)=eX+e-X,(e=2.71828) 设F(x)F(y)=4,g(x)g(y)=8
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已知F(x)=eX—e-X,g(x)=eX+e-X,(e=2.71828) 设F(x)F(y)=4,g(x)g(y)=8,求g(x+y)除以g(x-y)?
F(x)F(y)=(eX—e-X)(eY—e-Y)=e(X+Y)—e(X-Y)-[e-(X-Y)]+e-(X+Y)=g(x+y)-g(x-y)=4
g(x)g(y)=e(X+Y)+e(X-Y)+[e-(X-Y)]+e-(X+Y)=g(x+y)+g(x-y)=8
g(x+y)-g(x-y)=4 g(x+y)+g(x-y)=8
g(x+y)=6 g(x-y)=2 g(x+y)除以g(x-y) =3
g(x)g(y)=e(X+Y)+e(X-Y)+[e-(X-Y)]+e-(X+Y)=g(x+y)+g(x-y)=8
g(x+y)-g(x-y)=4 g(x+y)+g(x-y)=8
g(x+y)=6 g(x-y)=2 g(x+y)除以g(x-y) =3
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