sin7/5pai*cos(-11/6pai)+tan(-15/4pai)*tan7/5pai,计算得数,
计算下列三角函数值!sin(-7/6pai) cos(5/4pai) tan(-16/3pai)
cos(pai/15)×cos(2pai/15)×cos(3pai/15)×cos(4pai/15)×cos(5pai/
sin25/6pai+cos25/3pai+tan(-25/4pai)
已知cos(3pai/2-a)=2根号5/5,a属于(pai,3pai/2) 求tan(pai/4+2a)的值
已知sin(x-pai/4)=根号2/10,X属于(pai,5pai/4) 求sinx得值.求cos(2x-pai/6)
化简sin(-2/3pai+kpai)cos(pai/6+kpai)tan(pai/4+kpai),k属于z
[tan(pai-a)cos(2pai-a)sin(-a+3pai/2)]/[cos(-a-pai)sin(-pai-a
f x =sin(pai*x/4-pai/6)-2(cos pai*x/8)^2+1
已知函数f(x)=2sin(x+pai/6)-2cos,x属于[pai/2,pai].若sinx=4/5求f(x)的值,
化简:[cos(a+pai)*sin^2(a+pai)]/[tan^2(pai+a)*cos^3a]
已知a属于(pai/2,pai),tan(a+pai/4)=1/7,sin a+cos a=?
f(a)=[sin(pai-a)cos(2pai-a)tan(-a+3pai/2)]/[cos(-pai-a)]则f(-