方程组{100x+10y+z=48(x+y+z) {x+z=y+3 {100x+10y+z=100z+10y+x+198
解三元一次方程组,100x+10y+z=27(x+y+z) {x+y-z=1 (100z+10y+x)-(100x+10
(x+y-z)(x-y+z)=
若{x+3y+10z=0 则 (x+y-z)/(x-y+z)
100x+10y+z=48(x+Y+Z) x+Z=y+3 100x+10y+z-(100z+10y+x)=198 怎么解
三元一次方程组数学题x+2y+2z=33x+y-2z=72x+3y-2z=10x-y=2z-x=3y+z=-1x-y-z
100x+10y+z=27(x+y+z) x+z=y+1 100z+10y+x-100x-10y-z=99 解方程组
已知,方程组:4x-3y-7z=0 x+2y=10z 则(x-y+z)÷(x+y+z)=——
X+Y+Z=?
解方程组:3x+7y+z=31.5,4x+10y+z=42
解方程组{x(x+y+z)=6,y(x+y+z)=12,z(x+y+z)=18
解一道三元一次方程x+y+z=13,y-2=z,100z+10y+x+99=100x+10z+y.
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)