计算①1x2/1+2x3/1+3x4/1+```+19x20/1= ②1x4/1+4x7/1+7x10/1+```+91
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计算①1x2/1+2x3/1+3x4/1+```+19x20/1= ②1x4/1+4x7/1+7x10/1+```+91x94/1=
是否写反了
差/(小*大) =1/小 - 1/大 如 7/(3*10)=1/3 - 1/10 ; 1/(4*5)=1/4 - 1/5
但 1/(4*7) =3/(4*7) *(1/3)=(1/3)[1/4 -1/7]
1/(1*2)+1/(2*3)+1/(3*4)+...+1/(19*20)=1/1 -1/2+ 1/2 - 1/3 +1/3 - 1/4 +...+1/18- 1/19+1/19 -1/20
=1/1 -1/20 = 19/20...ANS
速算 大分子=各项分子和=1*19=19 ;大分母=第一项分母头*最后项分母尾=1*20=20 =>19/20
1,4,7,...,91等差 项数=(91-1)/3 +1=31
1/(1*4)+1/(4*7)+1/(7*10)+.+1/(91*94) =[1*31]/(1*94)=31/94...ANS
OR =1/3[1/1 - 1/4 +1/4 -1/7 +...+1/88- 1/91+1/91-1/94]=(1/3)(1- 1/94) =31/94
差/(小*大) =1/小 - 1/大 如 7/(3*10)=1/3 - 1/10 ; 1/(4*5)=1/4 - 1/5
但 1/(4*7) =3/(4*7) *(1/3)=(1/3)[1/4 -1/7]
1/(1*2)+1/(2*3)+1/(3*4)+...+1/(19*20)=1/1 -1/2+ 1/2 - 1/3 +1/3 - 1/4 +...+1/18- 1/19+1/19 -1/20
=1/1 -1/20 = 19/20...ANS
速算 大分子=各项分子和=1*19=19 ;大分母=第一项分母头*最后项分母尾=1*20=20 =>19/20
1,4,7,...,91等差 项数=(91-1)/3 +1=31
1/(1*4)+1/(4*7)+1/(7*10)+.+1/(91*94) =[1*31]/(1*94)=31/94...ANS
OR =1/3[1/1 - 1/4 +1/4 -1/7 +...+1/88- 1/91+1/91-1/94]=(1/3)(1- 1/94) =31/94
计算①1x2/1+2x3/1+3x4/1+```+19x20/1= ②1x4/1+4x7/1+7x10/1+```+91
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