高一数学;2log5;25 - 3log2;64=
2log5(25)-3log2(64)=?
高一数学(log5)^2+log2·log50
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log
高一数学设a=(lg2)²+(lg5)²+lg4lg5+2log5 10+log5 0.25 b=(
高一数学log2(4^x+4)=x+log2(2^(x+1)-3)
log2^25*log3^2倍根号2*log5^9=
我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log
一道高一数学题7设log2=a,log3=b,则log5^12=?
数学(log5 √2*log7 9)/(log5 1/3 *log7 3√4)+log2( √(3+√5)- log√(
(log3^4+log5^2)(log2^9+log2^根号3)
高一数学log2(√3+2)+log2(2-√3)
有关log的数学题①log2(2X+3)=0②log5(X)-1/3log5(8)=0③log2(X)+log4(X)=