z=(x-40)[20-(x-100)/10]

解三元一次方程组,100x+10y+z=27(x+y+z) {x+y-z=1 (100z+10y+x)-(100x+10 解3元一次方程组：x+y+z=70 x/30+y/20+z/40=2/5 x/40+y/20+z/30=10/23 x+y=10 y+z=15 z+x=20 求x,y,z等于多少? X+Y+Z=35 X/16+Y/10+Z/20=2.5 Z/16+Y/10+X/20=2.65怎么求x y z 若{x+3y+10z=0 则 (x+y-z)/(x-y+z) 解一道三元一次方程x+y+z=13,y-2=z,100z+10y+x+99=100x+10z+y. x+y=15 z+x=20 z+y=10 问xyz 各是多少 (x+y-z)(x-y+z)= 100x+10y+z=27(x+y+z) x+z=y+1 100z+10y+x-100x-10y-z=99 解方程组 100x+10y+z=48(x+Y+Z) x+Z=y+3 100x+10y+z-(100z+10y+x)=198 怎么解 x+y-2=5 2x+3y+z=10 x-2y-z=20 z=x