y=x^2/x-1,x∈[2,3]求最值

函数,y=3x/(x^2+x+1) ,x 函数y=3x/(x^2+x+1) （x 先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y 若全集I={(x,y)|x,y∈R},集合M={(x,y)|(y-3)/(x-2)},N{(x,y)|y=x=1},则( 1、x(x-y)(x+y)-x(x+y)^2 y=(x^2+x)/(x+1) (3x-y)^2+(3x+y)(3x-y),x=1,y=-2 {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 y=(2x*x-2x+3)/(x*x-x+1),求值域? 已知集合A={（x,y)| (y-3)/ (x-1)=2,x,y∈R},B={（x,y)| 4x+ay=16,x,y∈ 若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7 2(x+y) 3x+3y=24 x+y/2x x y/2y= 1