=2*(sin2xcosπ/6+cos2xsinπ/6) 怎么等于 =2sin(2x+π/6)

已知函数f（x）=sin2xcosφ+cos2xsinφ,x∈R,0＜φ＜π,f（π/4）=-√ 已知函数f(x)=sin2xcosφ-2cos²xsin(π-φ)-cos(π/2+φ) 1.化简y=f(x) 已知函数f(x)=sin2xcosφ-2cos²xsin(π-φ)-cos(π/2+φ) （-π/2＜φ＜π/ sin(π/3+x)=2/3 那么tan(π/6+x)等于多少? 已知sin(x+π/6)=1/3,求sin(5π/6-x)+sin^2(π/3-x) （2011•西城区二模）已知函数f(x)＝cos2xsin(x+π4)． 函数f(x)=2sin(2x+π/6)-1的值域怎么求 1)诺sin（π/6-x）=1/3,则cos（2π/3+2x）等于 已知sin(π/2-x)+sin(π-x)/cos(-x)+sin(2π-x)=2009,则tan(x+5π/4)等于? 1.已知sin(π/6-x)=1/4,sin(π/6+2x)=? 已知函数f(x)=2cos(x-π/6)sin(x+π/6)-√3*(sin(x-π/6))^2+sin(x-π/6)c 化简函数fx=sin(2x+π/6)+2sin^2x