√3/2sina-1/2cosa=√2/2 sin(a-π/6)=√2/2 解之得a=5/12π或11/12π 但是如果
若sinA+cosA/sinA-cosA=2,则sin(A-5π)*sin(3π/2-A)等于?
若sina+cosa/sina-cosa=2,则sin(a-5π)×sin(二分之三派-a)等于?请给出具体过程
已知sin(π-a)-cos(π+a)=√2/3 (π/2〈a〈π) 求⑴sina-cosa ⑵sina*cosa⑶si
化简:sin(a-B)cosa-1/2[sin(2a+B)-sinB]=?已知cos(a-π/6)+sina=4√3/5
sin(a-B)cosa-1/2[sin(2a+B)-sinB]=?已知cos(a-π/6)+sina=4√3/5则si
(2sin^2a+sin2a)/(1+tana) 整理 =[2sina(sina+cosa)]/[(sina+cosa)
若 cos2a/sin(a-π/4)= -√2/2,求cosa+sina的值.
若cos2a/sin(a-π/4)=-√2/2,则cosa+sina等于多少?
若cos2a/sin((a-(π/4))=-(√2)/2,则cosa+sina的值为
为什么cosa-sina=(√2)sin(π/4-a)谢谢大家
若(sina+cosa)/(sina -cosa)=2,则 sin(a-5π)*(乘) sin(3π/2 - a)等于?
√2(cos^2a-sin^2a)/(sina-cosa)=-2√2/2,则cosa+sina=?