(1)¾x²y³z÷3x³y (2)(4a²b³)²
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(1)¾x²y³z÷3x³y (2)(4a²b³)²÷(-¾a²b³) (3)27a^4b^5c÷(-3ab)
(4)-27m²n+9mn²-18mn (5)9m(x-3)+15n(3-x) (6)3x(a-b+1)-3y(b-a-1)+3z(1-b+a)
分解因式:(7)16(m+n)²-9(m-n)² (8)(7a²+2b²)²-(2a²+7b²)²
(9)a^5-a (10)x²-y²-(x+y) (11)a³-4a² +4a
(12)(a+b )²+2(a+b)+1 (13)(x^m+3 )+ (2x^m+2)y+(x^m+1)y²(14)m²(m-1)-4(1-m)²
(4)-27m²n+9mn²-18mn (5)9m(x-3)+15n(3-x) (6)3x(a-b+1)-3y(b-a-1)+3z(1-b+a)
分解因式:(7)16(m+n)²-9(m-n)² (8)(7a²+2b²)²-(2a²+7b²)²
(9)a^5-a (10)x²-y²-(x+y) (11)a³-4a² +4a
(12)(a+b )²+2(a+b)+1 (13)(x^m+3 )+ (2x^m+2)y+(x^m+1)y²(14)m²(m-1)-4(1-m)²
(1)解原式=3/4/3)*x*(2-3)y^(3-1)z
=y^2z/4x
(2)j解原式=16/[-(3/4)]*(a^2b^3)^(2-1)
=-64a^2b^3/3
(3)解原式=27/(-3)*a^(4-1)*b^(5-1)*c
=-9a^3b^4c
(4)解原式=-3*m^(2-1)*n^(1-2)-18mn
=-3m/n-18mn
(5)解原式=-(9/15)*m*(3-x)/n*(3-x)
=--3m/5n
(6)解原式=3x*(a-b+1)-(3y/3z)*[-(a+1-b)/((1-b+a)
=3x(a-b+1)+y/z
(7)=[4(m+n)+3(m-n)][4(m+n)-3(m-n)]
=(7m+n)(m+7n)
(8)=(7a^2+2b^2+2a^2+7b^2)(7a^2+2b^2-2a^2-7b^2)
=(9a^2+9b^2)(5a^2-5b^2)
=9*5*(a^2+b^2)(a^2-b^2)
=45(a^2+b^2)(a+b)(a-b)
(9)=a(a^4-1)
=a(a^2+1)(a^2-1)
=a(a^2+1)(a+1)(a-1)
(10)=(x+y)(x-y)-(x+y)
=(x+y)(x-y-1)
(11)=a(a^2-4a+4)
=a(a-2)^2
(12)=(a+b+1)^2
(13)题有问题
(14)=(m-1)[m^2-4(m-1)]
=(m-1)(m^2-4m+4)
=(m-1)(m-2)^2
=y^2z/4x
(2)j解原式=16/[-(3/4)]*(a^2b^3)^(2-1)
=-64a^2b^3/3
(3)解原式=27/(-3)*a^(4-1)*b^(5-1)*c
=-9a^3b^4c
(4)解原式=-3*m^(2-1)*n^(1-2)-18mn
=-3m/n-18mn
(5)解原式=-(9/15)*m*(3-x)/n*(3-x)
=--3m/5n
(6)解原式=3x*(a-b+1)-(3y/3z)*[-(a+1-b)/((1-b+a)
=3x(a-b+1)+y/z
(7)=[4(m+n)+3(m-n)][4(m+n)-3(m-n)]
=(7m+n)(m+7n)
(8)=(7a^2+2b^2+2a^2+7b^2)(7a^2+2b^2-2a^2-7b^2)
=(9a^2+9b^2)(5a^2-5b^2)
=9*5*(a^2+b^2)(a^2-b^2)
=45(a^2+b^2)(a+b)(a-b)
(9)=a(a^4-1)
=a(a^2+1)(a^2-1)
=a(a^2+1)(a+1)(a-1)
(10)=(x+y)(x-y)-(x+y)
=(x+y)(x-y-1)
(11)=a(a^2-4a+4)
=a(a-2)^2
(12)=(a+b+1)^2
(13)题有问题
(14)=(m-1)[m^2-4(m-1)]
=(m-1)(m^2-4m+4)
=(m-1)(m-2)^2
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