化简2(x²-½+2x)-4(x-x²+1)
化简{x²-2x分之x+2-x²-4x+4x分之x-1}除以X分之(x-1)(X-4)乘以(2-x)
(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3
化简(x+1/x)²+2(x+1/x)+2
(4x³)²×[x³-x(2x-1)]
4x²-{-3x²-[5x-x²-(2x²-x)]+4x},其中x=½
计算:2x/(x-2)(x+1)÷(1-x/x+1)-x²+2x/x²-4?
[(x+2)/(x²+2x)-(x-1)/(x²-4x+4)]÷(x-4)/x
化简,x²+4x /(2x-4)(x+4)-x+2/x² -4
(x+1)/(x²+3x+2)+(x²-2x)/(x²-4)
x²-2x分之x+2-x²-4x+4分之x-1
x+2/x²-2x-x-1/x²-4x+4计算
解方程(x²-x+4)x-(x-1)(x²+2)=x+7