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1-[(x-y)/(x+2y)]÷[(x+y)(x-y)/(x+2y)²]

来源：学生作业帮 编辑：大师作文网作业帮 分类：数学作业 时间：2024/11/18 11:11:42
1-[(x-y)/(x+2y)]÷[(x+y)(x-y)/(x+2y)²]
1-[(x-y)/(x+2y)]÷[(x+y)(x-y)/(x+2y)²]
=
1-[(x-y)/(x+2y)]÷[(x+y)(x-y)/(x+2y)²]
1-[(x-y)/(x+2y)]÷[(x+y)(x-y)/(x+2y)²]
=1-[(x-y)/(x+2y)]×[(x+2y)²/(x+y)(x-y)]
=1-(x+2y)/(x+y)
=(x+y-x-2y)/(x+y)
=-y/(x+y)
再问： 这100%正确吗?
再答： 嗯，是
[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y 1、x(x-y)(x+y)-x(x+y)^2 (1)(x^2/x)-y-x-y [x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013 {(x,y) |x|+|y| x>y?x:y 1.[(x-y)^2-2(y -x)]÷(x-y) (2x-y)²-4(x-y)(x+2y) 化简：（2x-y)²-4(x-y)(x+y) 【(1)/(x-y)+(1)/(x-y)】÷(2x)/(x²-2xy+y²) 【(x-y)^2+(x+y)(x-y)】除以 2x (1)(x+y)^2-(x-y)^2