求证:sin3a*sin^3a+cos3a*cos^3a=cos^3 2a
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求证:sin3a*sin^3a+cos3a*cos^3a=cos^3 2a
cos2a=cos^2a-sin^2a=1-2sin^2a=2cos^2a-1
cos^2a=(1+cos2a)/2
sin^2a=(1-cos2a)/2
代入原式=sin3axsinax(1-cos2a)/2+cos3axcosax(1+cos2a)/2
=1/2(sin3axsina+cos3axcosa)+1/2cos2a(cos3axcosa-sin3axsina)
=1/2cos(3a-a)+1/2cos2acos(3a+a)
=1/2cos2a(1+cos4a)
=1/2cos2ax2cos^2(2a)=cos^3(2a)
cos^2a=(1+cos2a)/2
sin^2a=(1-cos2a)/2
代入原式=sin3axsinax(1-cos2a)/2+cos3axcosax(1+cos2a)/2
=1/2(sin3axsina+cos3axcosa)+1/2cos2a(cos3axcosa-sin3axsina)
=1/2cos(3a-a)+1/2cos2acos(3a+a)
=1/2cos2a(1+cos4a)
=1/2cos2ax2cos^2(2a)=cos^3(2a)
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