(√ 2 sinx )-sin(x-π/4) 化简

sinx+cosx=√2sin(x+π/4) 化简f(x)=4sinx*sin^2（(π+2x）/4)+（cosx+sinx）（cosx-sinx） 化简sin^4x/sinx-cosx - (sinx+cosx)cos^2x/tan^2x-1 求证sinx-cosx=根号2sin(x-π/4) |sin(x+π/2)|-|sinx|求导过程? 使f(x)=sinx+cosx=√2*sin(x+π/4) 步骤是什么 怎样使f(x)=sinx+cosx=√2*sin(x+π/4) 2sin(x-π/4）sin（x+π/4）=（sinx-cosx）（sinx+cosx）=-cos2a 已知函数f(1+cotx)sinx^2-2sin(x+π/4)sin(x-π/4) 已知sinx+cosx=2/3.化简((√2)sin(2x-π/4)+1)/(1+tanx) 函数fx=sinx+cosx导数怎么是√2sin(x+π/4)? 化简[sin^2(x)]/(sinx-cosx)-(sinx+cosx)/[tan^2(x)-1]-sinx