sin^4π/8 +cos^4π/8
化简:[1+2sin(α+2π)*cos(α-2π)]/[sin(α+4π)+cos(α+8π)]
sin(θ-5π)cos[(-π/2)-θ]cos(8π-θ)}/sin[θ-(3π/2)]sin(-θ-4π)
求SINπ/64 COSπ/64 COSπ/32 COSπ/16 COSπ/8
d/dx sin^8(cos(4x))
(cosπ/8+sinπ/8)(cos^3π/8-sin^3π/8)
(cos π/8+ sin π/8 ) (cos^3 π/8+sin^3 π/8 )的值.
怎样化简函数 cosπ/4cosπ/3-sinπ/4sinπ/3
高一数学 sinαcosα=1/8,且π/4<α<π/2,则 cosα-sinα的值为?
同角三角函数问题若sinβ*cosβ=1/8,π/4<β<π/2,那么sinβ-cosβ的值为
已知sinα×cosα=1/8 且π/4 <α<π/2 则cosα-sinα的值
化简4sin派/8*cos派/8*(cos^2派/8-sin^2派/8)
8sin(π/32)cos(π/32)cos(π/16)cos(π/8),求值