∵x>22x>15/1510；fx=10/15^x^22-22x 10

X/15 + X/12 + X/10 = 1365,求X, (x-22)+(x-24)+(x-27)+(x-20)=x 已知函数fx=ax^2+bx+1,Fx={fx,x>0 -(fx),x 1x+2x+3x+4x+5x+6x+7x+8x+9x+10x+11x+12x+13x+14x+15x=550 已知函数fx=x²+1(x≤0) -2x(x＞0) 若f(x)=10则x= x+x=x+15 化简|x-5|+|x+10|-|x-15|, (2x^-5x+2/6x^+13x+6)*(6x^-5x-6/6x^-17x+10)*(12x^+8x-15/2x^-x 35(X-2)+15(5X-6)=(22X-51)+21(3X-4) 35(x-2)-15(5x-6)=(22x-63)-21(3x-4)咋算? 130%x+x=4.6 x÷50%=10 x/9-x/15=16% x-4x=102 x-0.8x=22