14x+4y+z=200,x+y+z=100求解x,y,z

(x+y-z)(x-y+z)= X+Y+Z=? 求解三元一次方程组：｛x+y/2=y+z/3=z+x/4 x+y+z=27 x+y+z=4 x-2y+z=-2 x+2y+3z=0求解 f(x,y,z,w)=x*(x+y)*(x+y+z)*(x+y+z+w) x y z x+y--- = --- = ---- ----y+Z z+x x+y ,求 z 的值 .求 x+y---- 1.设X ,Y,Z 成等差数列,代数式（X-Z）*（X-Z）+ 4(X-Y)(Z-Y)= 已知x+y-z/z=x-y+z/y=-x+y+z/x,且xyz不等于0,求分式[(x+y)(x+z)(y+z)]/xyz 若z分之x+y+z=y分之x-y+z=x分之-x+y+z,求xyz分之(x+y)(y+z)(z+x) y+z÷x=Z+X÷y=X+Y÷z,X+Y+Z不等0求X+Y-Z÷X+Y+z值 (x+y-z)/z=(y+z-x)/x=(z+x-y)/y 求(x+y)(y+z)(z+x)/xyz x分之y+z=y分之z+x=z分之x+y(x+y+z不等于0）,求x+y+z分之x+y-z