x+y+z=59,15x:12y=3:2,12y：8z=2:1

如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y, x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, 已知{x：y：z=1：2：3,x+y+z=12,求x、y、z的值 ①x+y+z=6 3x-y+2z=12 x-y-3z=-4 ②x+y-z=2 4x-2y+3y+8=0 x+3y-2z- 1.x+y+z=21,x-y=1,2x+z-y=13.2.3x+2y+z=13,x+y+2z=7 ,2z+3y-z=12 x+2y=3 x+y+z=36 2x+y+z=15 2y=3z x-y=1 x+2y+z x-z=-1 2x+z-y=1 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) {x+y+z=1;x+3y+7z=-1;z+5y+8z=-2 x:y=1:2 z:x=3:1 x +y+z=12 1.x+y=16,y+z=12,z+x=102.3x-y+z=4,2x+3y-z=12,x+y+z=63.x+y+z=6 3x-y+z=3 2x+y-3z=11 x+y+z=12 解方程 解方程组{3x+y-z=4,2x-y+3z=12,x+y+z=6}