(X+Z)(X-Z)+x(X+2Y)怎么解?
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(X+Z)(X-Z)+x(X+2Y)怎么解?
方程写完了吗,没有有等于号的话此方程有无数个解
再问: 不好意思。题出错了。是(y+z)(y-z)+x(x+2y)是这个。怎么解?按你的方法能得到(x-y-z)(x-y+z)
再答: 用平方差公式算出(y+z)(y-z)=y²-z² 然后把x(x+2y)去括号得x²+2xy (y+z)(y-z)+x(x+2y)就等于 =y²-z²+x²+2xy =x²+2xy+y²-z² =(x+y)²-z² 然后用平方差的逆定理a²-b²=(a+b)(a-b) =(x+y+z)(x+y-z) 懂了吗答案不是(x-y-z)(x-y+z)
再问: 不好意思。题出错了。是(y+z)(y-z)+x(x+2y)是这个。怎么解?按你的方法能得到(x-y-z)(x-y+z)
再答: 用平方差公式算出(y+z)(y-z)=y²-z² 然后把x(x+2y)去括号得x²+2xy (y+z)(y-z)+x(x+2y)就等于 =y²-z²+x²+2xy =x²+2xy+y²-z² =(x+y)²-z² 然后用平方差的逆定理a²-b²=(a+b)(a-b) =(x+y+z)(x+y-z) 懂了吗答案不是(x-y-z)(x-y+z)
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