提问A={y/y^2-(a^2+a+1)y+a(a^2+1)>0} B={Y/Y^2-6y+8
因式分解 (1)6(x-y)^3-3y(y-x)^2 (2)x(x-y)(a-b)-y(y-x)(
集合A={y|y=log2x},B={y|y=(1/2)^x},则A∩B=?
A*y"+B*(1+y')^(1/2)=0 求原函数Y~
#include main() {int y,a; y=2,a=1; while(y--!=-1) {do{a*=y;a
已知集合A={y|y^2-(a^2+a+1)y+a(a^2+1)>0},
已知集合A={(x,y)|(y-3)/(x-2)=a+1}B={(x,y)|(a^2-1)x+(a-1)y=15},当a
1.已知集合A={(x,y)|y=2x+1},B={(x,y)|y=x+3},a∈A,b∈B,求a
define A(x,y) x*y-x/y main(){int a=5,b=2,y;y=A(a+b,a-b);prin
已知集合A{y/y平方-(a*a+a+1)y+a(a*a+1)>0} B{y/y=1/2x平方-x-5/2,0≤x≤3}
A={y|y=x2-4x+6,y属于N},B={y|y=-x2-2x+18,y属于N},求A交B.
已知集合A={y|y+2/y-5>=1/2},B={y|y=ax^2-6x+4a,其中a不等于0,x属于R},已知B是A
已知集合A={(x,y)|(y-2)/(x-1)=a+2,x,y∈R},B={(x,y)|(a²-4)x+(a