因式分解问题(x+2y)²-4z²
来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/09/24 13:13:18
因式分解问题(x+2y)²-4z²
(x+2y)²-4z²
a²(a-b)+b²(b-a)
-196a²b²+81x4次方y²
4(x+2y)²-25(x-2y)²
4(x+y+z)²-9(x-y-z)²
急等着用
(x+2y)²-4z²
a²(a-b)+b²(b-a)
-196a²b²+81x4次方y²
4(x+2y)²-25(x-2y)²
4(x+y+z)²-9(x-y-z)²
急等着用
解
(x+2y)²-4z²
=(x+2y)²-(2z)²
=(x+2y-2z)(x+2y+2z)
a²(a-b)+b²(b-a)
=a²(a-b)-b²(a-b)
=(a-b)(a²-b²)
=(a-b)(a-b)(a+b)
=(a-b)²(a+b)
-196a²b²+81x^4y²
=(9x²y)²-(14ab)²
=(9x²y-14ab)(9x²y+14ab)
4(x+2y)²-25(x-2y)²
=[2(x+2y)]²-[5(x-2y)]²
=[2(x+2y)-5(x-2y)][2(x+2y)+5(x-2y)]
=(14y-3x)(7x-6y)
4(x+y+z)²-9(x-y-z)²
=[2(x+y+z)]²-[3(x-y-z)]²
=[2(x+y+z)-3(x-y-z)][2(x+y+z)+3(x-y-z)]
=(5y-x+5z)(5x-y-z)
(x+2y)²-4z²
=(x+2y)²-(2z)²
=(x+2y-2z)(x+2y+2z)
a²(a-b)+b²(b-a)
=a²(a-b)-b²(a-b)
=(a-b)(a²-b²)
=(a-b)(a-b)(a+b)
=(a-b)²(a+b)
-196a²b²+81x^4y²
=(9x²y)²-(14ab)²
=(9x²y-14ab)(9x²y+14ab)
4(x+2y)²-25(x-2y)²
=[2(x+2y)]²-[5(x-2y)]²
=[2(x+2y)-5(x-2y)][2(x+2y)+5(x-2y)]
=(14y-3x)(7x-6y)
4(x+y+z)²-9(x-y-z)²
=[2(x+y+z)]²-[3(x-y-z)]²
=[2(x+y+z)-3(x-y-z)][2(x+y+z)+3(x-y-z)]
=(5y-x+5z)(5x-y-z)
因式分解x²-y²-z²+2xy
因式分解x²-y²-z²+2yz
25(x-y)²-10(y-z)+1因式分解
因式分解:(x²+y²-z²)²-4x²y²
多项式因式分解:1,(x+y)²-8(x+y-z) 2,0.333²×4-1.222²×9
因式分解:(x+y+z)的平方-4(x-y-z)
因式分解2(x^2y^2+y^2z^2+z^2x^2)-(x^4+y^4+z^4)
(x+2y-7z)^3+(3x-4y+6z)^3-(4x-2y-z)^3 因式分解
因式分解:x^-4xy+4y^-z^
因式分解 (x+y+z)^2+yz(y+z)+xyz
因式分解x²-y²-z²=2yz+2x+1
先因式分解,再求值.xyz²+xy²z+x²yz,其中x=2/5,y=7/20,z=1/4