x:y=3:2;y:z=5:4;x+y+z=66加减法过程怎么算?
用加减法解{2X+3Y+Z=38 3X+4Y+2Z=56 4X+5Y+Z=66
用加减法解下列方程组:{2x+3y+z=38,3x+4y+2z=56,4x+5y+z=66
用加减法解三元一次方程组 2x+3y+z=38 3x+4y+2z=56 4x+5y+z=66
三元方程求救要过程2x+3y+z=383x+4y+2z=564x+5y+z=66x:y=5:3x:z=7:32x-y-z
2x+3y-4z=0.,3x+4y+5z=0,则x+y+z/x-y+z详细的解题过程
用加减法解下列三元一次方程组:2x+3y-z=9 x+y+z=15 5x-4y-z=0 过程一定一定要清楚一点啊!
x/2=y/3=z/5 x+3y-z/x-3y+z
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
x=3,y=4,z=5,求以下表达式的值,怎么算 (x && y)==(x || z) (x>y)+(y!=z) ||
已知3x-2y-5z=0,2x-5y+4z=0,且x,y,z均不为0,求3x*x+2y*y+5z*z/5x*x+y*y-
已知3x=4y,2y=5z,试求x:y:z