[数学题]若|x-√2|+(y-1)^2+√(z+5),则xyz=?
若xyz满足条件:(√x)+(√y-1)+(√z-2)=1/4(x+y+z+9),则xyz等于
若x+y+z+9=(√x+√y-1+√z-2),则xyz=
若实数x,y,z满足条件√x+√y-1+√z-2=1/4(x+y+z+9),求xyz的值
若x=y/2=z/5,x+y+z=16,xyz=?
已知xyz满足x+y+z=30,3x+y-z=50,设t=5x+4y+2z 1当t=40时,求xyz的值 2若xyz均为
已知实数xyz满足|x-2y|+2√(2y+z)+z-2z+1=0,求x+y+z的值
已知xyz适合关系式√3x+y-z-2+√2x+y-z=√x+y-2011+2011-x-y,试求xyz的值
先化简再求值3xyz+2(x^2y+y^2z-xyz)-xyz+2z^2x x=1 y= -1 z=2
【初二数学题】已知xyz=1,x+y+z=2,x²+y²+z²=16,求1/(xy+2z)
已知xyz均为实数,若x+y+z=1求证√3x+1√3y+2√3z+3
已知 x,y,z都是正实数,且 x+y+z=xyz 证明 (y+x)/z+(y+z)/x+(z+x)/y≥2(1/x+1
已知x^2+y^2+z^2=1,求证x+y+z-2xyz