利用倍角公式推出：sin4a=,cos4a===,tan4a=,sina=,cosa==

来源：学生作业帮编辑：大师作文网作业帮分类：数学作业时间：2024/11/11 08:50:45

利用倍角公式推出：sin4a=__,cos4a=__=__=__,tan4a=__,sina=__,cosa=__=__=__,tana=__?

sin4A=-4*(cosA*sinA*(2*sinA^2-1))
cos4A=1+(-8*cosA^2+8*cosA^4)
tan4A=(4*tanA-4*tanA^3)/(1-6*tanA^2+tanA^4)
再问： sina,coa,tana的呢

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