(x1x2²+x1²x2-x1+x2)/x1x2怎么分解因式?
(x1-x2)-[a(x1+x2)]/x1x2 这个要怎么化简啊?怎么变成这样[(x1-x2)(x1x2-a)]/x1x
(x1-x2)+(x2-x1)/x1x2 = (x1-x2)(1- 1/x1x2)
求化简过程,(x1+a/x1)-(x2+a/x2)=(x1-x2)/x1x2(x1x2-a)
x1-x2)+x1x2分之4(x2-x1)怎样化简成((x1-x2)(1-x1x2分之4)
(x2-x1)/(x1x2)怎么化简
(x1-x2)+(x2-x1)/(x1x2)=(x1-x2)(x1x2-1)/x1x2 这一步怎么推出来的,
(x1-x2)+x1-x2/x1x2怎么就成了(x1-x2)(1-1/x1x2),
设3x²+2x-3=0,两根为x1,x2,求①x2/x1 + x1/x2 ②x1^2+x2^2-4x1x2
x1x2是方程2X²-3X-8=0的两根,则X1+X2= ,X1X2= ,X1²+X2²=
(X1-X2)+(X2-X1/X1X2) 化简成(X1-X2)(1-1/X1X2) 怎么化简的? 两个数相加怎么就变成想
已知3x²-7x+2=0有两根为x1x2,则x1x2²+x1²x2=?
设f(x1,x2,x3)=x1²-4x1x2+8x1x3+4x2²+4x2x3+x3²,求