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.m(x-y)²-x+y 5(y-x)²+3(x-y) 15*(a-b)²-3y(b-a)

来源:学生作业帮 编辑:大师作文网作业帮 分类:数学作业 时间:2024/11/12 13:14:13
.m(x-y)²-x+y 5(y-x)²+3(x-y) 15*(a-b)²-3y(b-a) 6(m-n)³-12(n-m)²
13/x-4-10/x-3=1/x-1
.m(x-y)²-x+y 5(y-x)²+3(x-y) 15*(a-b)²-3y(b-a)
m(x-y)²-x+y
=m(x-y)²-(x-y)
=(x-y)(mx-my-1)

5(y-x)²+3(x-y)
=5(x-y)²+3(x-y)
=(x-y)(5x-5y+3)

15*(a-b)²-3y(b-a)
=15(a-b)²+3y(a-b)
=3(a-b)(5a-5b+y)

6(m-n)³-12(n-m)²
=6(m-n)³-12(m-n)²
=6(m-n)²(m-n-2)

13/(x-4)-10/(x-3)=1/(x-1)
去分母,两边同时乘以(x-4)(x-3)(x-1)得:
13(x-3)(x-1)-10(x-4)(x-1)=(x-3)(x-4)
13(x²-4x+3)-10(x²-5x+4)=x²-7x+12
整理:2x²+5x-13=0
解得x1=(-5-√129)/4,x2=(-5+√129)/4
x1,x2均是原方程的根