微积分f''(x)+f'(x)-2f(x)=0,f''(x)+f(x)=2e^x,f(x)=?

f(X)=f(X+2)(x 若f(x)=e^x+2∫(0 1)f(x)dx 求f(x) x-2 ,X>=0 f(x)=f[f(x+5)],x分段函数f(x)= x-2 ,X>=0 f[f(x+5)],x f(x)=e^x/x,求∫f'(x)dx/1+f^2(x)? f(x+2)>=f(x)+2,f(x+3) f（2-x）=f(x) 已知函数f(x)满足f(x)=f'(1)e^(x-1) - f(0)x+(1/2)x^2 (2)若f(x)≥(1/2)x F(X)满足F(x)+2f(x分之1)=3X,求f(x) 已知f(x)满足2f(x)+f(1/x)=3x,求f(x) 已知f(x)满足2f(x)+f(1/x)=3x,求f(x)? 设函数f(x)满足f(x)+2f(1/x)=x,求f(x) 已知f(x)满足2f(x)+f(-x)=-3x+1,求f(x)