(10x+10y)/xy化简
x y xy=10怎么算
xy+yx=10x,y是多少
[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-
xy=(x-10)(y+1) xy=(x-15)(y+3) 解方程组.
化简xy-1-x+y
[(xy+2)(xy-2)-2x^2y^2+4]/xy,其中x=10,y=-1/25
[(xy+2)(xy-2)-2x^2y^2+4]/(xy),其中:x=10,y=-1/25
已知2x+xy=10,3y+2xy=6.求4x+8xy+9y=?
x的平方y+10xy+25y 因式分解
已知x^2+10xy+25y^2-1=0,化简x^3+5x^2y+x^2..
先化简,再求值:[-xy/(x-y)^2]^4*(x^2-xy/x)3*x^4/y^10÷(x/xy-y^2)^5
若x+y=10 xy=-1 则x²+y²=(x+y)²-2xy=