4x-y+z=25,6x-z+2y=22,x+3y+z=-2

试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, 1.x+y=16,y+z=12,z+x=102.3x-y+z=4,2x+3y-z=12,x+y+z=63.x+y+z=6 x/2=y/3=z/5 x+3y-z/x-3y+z 如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y, x+y+z=4 2x+3y-z=6 3x+2y+2z=10 2x-y+2z=-17 3x+y-3z=-4 x+y+z=6 2x+5y+4z=6,3x+y-7z=-4,x+y-z=? {2x+3y-4z=-5 x+y+z=6 x-y+3z=10 解方程组{3x+y-z=4,2x-y+3z=12,x+y+z=6} 解方程{3x -y+z=4 2x+3y-z=12 x+y+z=6 解方程组：x+y+z=4,x+y+2z=5,3x+y-z=6