(x+3y+2)(x+2-3x) 咋算
有这样一道题:"计算(2*x*x*x-3*x*x*y-2*x*y*y)-(x*x*x-2*x*y*y+y*y*y)+【-
因式分解3x^2(x-y)+6x(y-x)
[(3x+y)(x-y)-(2x+3y)(x-y)]*(x-y)
化简:(x-3y)(x+y)-(x-2y)(x+2y)-(x-y)平方
【x-3y][x+y]-[x-2y][x +2y]-[x-y
x/x-y*y^2/x+y-x^3y2/x^4-y^4/x^2/x^2+y^2
[x(x^2y^2-xy)-y(x^2-x^3y)]/3x^2y
计算(x+y)(x+y)^2(-x-y)^3
数学(x-y)^5*(y-x)^3*(x-y)^2
已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
化简:{2/3x-2/(x+y)[(x+y)/3x-x-y]}/【(x-y)/x】的负二次方