(x+y)/6+(x-y)/10=1,(x+y)/6-(x-y)/10=5
已知X,Y,满足(X+3Y)(X-3Y)=-10(Y^2-6/5)和2X(Y-1)+4(1/2X-1)=0
用加减法解方程组:{(x+y)/6+(x-y)/10=3 (x+y)/6+(y-x)/10=-1
解方程组x+y/6+x-y/10=3,x+y/6+y-x/10=-1
已知x,y满足约束条件{2x+5y>=10,2x-3y>=-6,2x+y
3x+2y=6 ,5x+6y=10那么x+y=?
2x+y=4x-y-1/2=10+6x+2y/4
{4/(x+y)+6/(x-y)=3 {9/(x-y)-1/(x+y)=1
6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
已知4x+y-4x-6y+10=0,求(三分之二x√9x+y√y分之x)-x√x分之1-5x√x分之y)的值
2X+Y+Z=10,X+2Y+Z=-6,X+Y+2Z=8 5X+4Y-3Y=13,2X-3Y+7Z=19,3X-Y=2X
x+y=6 10x+y≤42