log2^9×log3^2=?

log2(3)+log3(5)+log3(2)=? (log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7) log2 4=2log3 9=3 log2^25*log3^2倍根号2*log5^9= log2^5*log3^2倍根号2*log5^9= 已知log3^2=a则log2^9等于多少 (log3^4+log5^2)(log2^9+log2^根号3) log2(3)=a,log3(7)=b.log12(56)=log3(7*8)=log3(7)+3log3(2) log2 3×log3 7=log2 7 log3 7·log2 9·log49 a=log4 1/2,则a= [log2(3)+log4(9)][log3(4)+log9(2)]等于 我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log