{x+y-z=2 4x-2y+3z+8=0 x+3y-2z-6=0怎么解?

①x+y+z=6 3x-y+2z=12 x-y-3z=-4 ②x+y-z=2 4x-2y+3y+8=0 x+3y-2z- 如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y, 请问怎么由2x-3y+z=0 ,3x-2y-6z=0 得到x=3z,y=4z 解三元一次方程：x+y-z=0,2x+y+z=7,x-3y+z=8 已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3 已知4x-3y+z=0,x+2y-8z=0,xyz不等于0,求x+y-z/x-y+2z的值 已知方程组4x-y+3z=0 2x+y+6z=0且xyz不等于0,则x/y+y/z+z/x是多少 4x-3y-6z=0,x+2y-7z=0是一个方程组,那么x-y+z/x+y+z的值等于 已知有理数x、y、z满足条件|x-z-2|+(3x-6y-7)^2+|3y+3z-4|=0,求x、y、z 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 若4x-3y-6z=0,x+2y-7z=0,求代数式5x*5x+2y*2y-z*z/2x*2x-3y*3y-10z*10 x-3y+z=0,3x-2y-4z=0,则x:y:z=多少?