10X+Y-27=10Y+X
已知/x/+x+y=10,/y/+x-y=12.求x+y的值
已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y
X+Y=7(100X+Y)-(10Y+X)=(10Y+X)-(10X+Y)
已知实数x,y满足|x|+x+y=10、x+|y|-y=12,则x+y的值?
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
1.x+x+x+y+y=6.4 y+y+y+x+x=7.1 x= ( ) y=( ) 2.1,4,7,10,13……这串
第一道:已知X的平方+Y的平方-4X+10Y+29=0.求分式X+Y/X-Y+X-Y/X+Y的值.
解三元一次方程组,100x+10y+z=27(x+y+z) {x+y-z=1 (100z+10y+x)-(100x+10
已知2x-y=10,求式子[(x^2+y^2)-(x-y)^2+2y(x-y)]/4y (4xy-2y²)/4
(7x-10y)-(-10y-5x)=?
y=ln(1+x),求y^10(x)?
x+y=6 10x+y≤42