f(x)=2sin(2x+π/6)
已知函数f(x)=sin(2x+π/6)+sin(2x+π/6)+2cos²x
已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)=sin(2x-π/6) ,
已知函数f(x)=sin(π-x)sin(π2-x)+cos2x
函数f(x)=根号3sinωx+cosωx(ω>0)怎样变为f(x)=2sin(ωx+π/6)
化简f(x)=2coscos(π/6-x)-√3 sin²x+sinxcosx
f(x)=sin(x+派/6)+2sin 求导
已知函数f(x)=2sin(2x+π/6)求函数f(x)的最大值
已知f(x)=2sin(2x+π/6),
已知f(x)=-1/2+sin(π/6-2x)+cos(2x-π/3)+cos平方x.
设函数f(x)sin(x+π/3)+2sin(x+π/3)-根号3cos(2π/3-x) (1)求f(π/6),f(π/
f(x)=sin(nπ/3),f(1)+f(2)+...+f(2010)等于
已知f(x)=2sin(2x-π6