2sin(πx/4-π/4)+6<2sin(πx/4-3π/4)+8的解集
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1
已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)=sin(2x-π/6) ,
已知函数fx=(1+1/tanx)sin^x-2sin(x+π/4)sin(x-π/4)
已知sinα(x+π/6)=1/4,则sin(5π/6-x)+sin(π/3-x)的平方=?
已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/2) 化简为sin的形式
已知函数f(x)=(1+cotx)sin^2(x)-2sin(x+π/4)sin(x-π/4)
已知函数f(x)=sin^2 x+2根号3sinxcosx+sin(x+π/4)sin(x-π/4),x属于R,求f(x
1.已知sin(π/6-x)=1/4,sin(π/6+2x)=?
y=sin(π/4+x/2)sin(π/4-x/2) =sin(π/4+x/2)sin[π/2-(π/4+x/2)]
已知sin(x+π/6)=1/4,则sin(7π+x)+sin^2(5π/6-x)的值
求化简数学公式哦[3sin^2(x/2)+cos^2(x/2)-4sin(x/2)cos(x/2)]/tan(π+x)化
已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/4)