(x-2)²=0
f(x)=-x^2+2x(x>0) 0(x=0) x^2-2x(x
(x)-2x·x-x-2x+1=0求x的值,
设集合A={X|X²-3X+2=0},B={X|X²+2(a+1)X+(a²-5)=0}
已知X不等于0,且M=(X²+2X+1)(X-2X+1),N=(X²+X+1)(x²-X+
判断函数奇偶性,快,f(x)=a(x属于R)f(x)=x^2 (1-x) ,x大于等于0x^2 (1+x) ,x
已知f(x)= -x^2-2x g(x)= 分段函数 x+1/4x(x>0),x+1(x
(2x-2)(x-1)=0 x(x-5)=5x-10
2x²+7x+1=0 x(x-1)=3x+7
f(x)= x^2+1 x≥0
x(x-14)二0*x平方十|2x十27=0,x平方=x+56,x(5x+4)=5x+4,4x平方-45=3|x,-3x
lim(4x^3-2x^2+x)/(3x^2+2x)=?(x->0)
已知,集合A={x|(x+2)(3-x)>0},B={x|x的平方-4x+a