计算:√3sin(-20/3∏)-cos13/4π×tan(-37/4π)
计算:sin25π/6+cos25π/4+tan(-25π/4)+sin(-26π/3)
sin(-21π/4) cos(-20π/3) tan(-19π/6)=
三角函数计算:若sinθ+cosθ=√2 则tan(θ+π/3)=?
SIN(-7/6π),cos(15/4π),tan(-8/3π),tan(33/4π)
数学角度计算cos(π/3)-sin^2(π/4)+1/3*tan^2 (π/3)*sin(3π/2)+cosπ=?注:
已知tan(α+π/4)=3,求cosα+2sinα/cosα-sinα的值
计算sin(-α-5π)*cos(α-2分之π)-tan(α-2分之3π)*tan(2π-α)
tan{arcsin[cosπ/4]+arccos[sinπ/3]+arctan√3}
高一三角函数计算求 具体方法!(1)cos310*tan(-108)(2)sin(5π/4)*cos(4π/5)*tan
已知sin(a-π/4)=7√2 ̄/10,cos 2α=7/25,求sinα及tan(α+π/3)
已知tan(π-α)=2,求sinα-2sinαcosα-cosα/4cosα-3sinα的值
计算sin(-π+π/3)+tan(3π/2-π/6)+sin15,