已知函数f(x)=2x+3/3x,数列{an}满足a1=1,an+1=f(1/an),n为正整数
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已知函数f(x)=2x+3/3x,数列{an}满足a1=1,an+1=f(1/an),n为正整数
(2)令Tn=a1a2-a2a3+a3a4-a4 a5+……-a2n a2n+1,求a2n-1-a2n+1及Tn
(2)令Tn=a1a2-a2a3+a3a4-a4 a5+……-a2n a2n+1,求a2n-1-a2n+1及Tn
A(n+1)=f(1/An)
A(n+1)=An(2/An +3)/3=2/3 +An
A(n+1)-An=2/3
Tn=A2(A1-A3)+A4(A3-A5)+...+A(2n)(A(2n-1)-A(2n+1))
=A2(-2d)+2A2(-2d)+..nA2(-2d)
=A2(-2d)(1+2+3+4+...+n)
A(n+1)=An(2/An +3)/3=2/3 +An
A(n+1)-An=2/3
Tn=A2(A1-A3)+A4(A3-A5)+...+A(2n)(A(2n-1)-A(2n+1))
=A2(-2d)+2A2(-2d)+..nA2(-2d)
=A2(-2d)(1+2+3+4+...+n)
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