设tan2a=2根号2,a属于(π/2,π),求(2cos^a/2-sina-1)/(sina+cosa)

设tan2a=2根号2,a属于(π/2,π),求(2cos^a/2-sina-1)/(sina+cosa) 设tan2a=-2根号2,求cos^a/根号2-sina-1/2sin(a+/pai4) 已知cosa=-1/3,a∈(π/2,π),求sina和tan2a的值 sina=3/5,a∈(0,π/2),求tan2a+根号2cos(a-π/4) tan2a=-2根号2,2a属于(90`,180`),求 [2cos^2(a/2)-sina-1]/根号2sin(a+4 tan2a=-2根号2,2a属于(90`,180`),求[cos^2(a/2)-sina-1]/根号2sin(a+45` 设tan2a=-2根号2,2a在180度与360度之间,求[2cos^2(a\2)-sina-1]/根号2(a+pi/4 已知[sina(a-π/4)]/cos(π+2a)=根号2,则sina+cosa=? 证明(1-cos^2a)/(sina+cosa)-(sina+cosa)/(tan^2a-1)=sina+cosa 证明(1-cos^2a)/(sina-cosa)-(sina+cosa)/(tan^2-1)=sina+cosa 已知sina-cosa=1/5,且a属于(0,π/2) (1)求sina和cosa的值 （2）求cos（2a-π/4)的 sina+cosa=-3/根号5,且|Sina|>|cos a|,求tan(a/2)