sin^2x+cos^2x)(sin^4x-sin^2xcos^2x+cos^4x) =sin^4x-sin^2xcos

sin^2x+cos^2x)(sin^4x-sin^2xcos^2x+cos^4x) =sin^4x-sin^2xcos (1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x 化简cos^4x+sin^2xcos^2x+sin^2x 求函数f(x)=(sin^4x+cos^4x+sin^2xcos^2x)/2 求函数y=2sin xcos x+2sin x+2cos x+4的值域 求sin^4x+cos^4x+4sin^2xcos^2x-1的最小正周期及值域. 求证 sinˇ4X+sin²Xcos²X+cos²X = 1 求函数f（x）=（sin⁴x+cos⁴x+sin²xcos²x）/（2-si f(x)=a(sin^6x+cos^6x)+b(sin^4x+cos^4x)+6sin^2xcos^2x的值与x无关且等 求函数f(x)=sin^4x+cos^4x+sin^2xcos^2x/2-2sinxcosx-1/2sinxcosx+1 证明sin4次方x+cos四次方x=1-2sin²xcos²x 已知函数f(x)=a(cos^2 x+sin xcos x)+b.