计算:(m+1/2n-1)(m-1/2n+1)-(m-1)^2+(1/2n+1)^2
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计算:(m+1/2n-1)(m-1/2n+1)-(m-1)^2+(1/2n+1)^2
=[m+(n/2-1)][m-(n/2-1)]-(m-1)²+(n/2+1)²
=m²+(n/2-1)²-(m²-2m+1)+(n/2+1)²
=m²+n²/4-n+1-m²+2m-1+n²/4+n+1
=n²/2+1+2m
再问: m²+(n/2-1)²-(m²-2m+1)+(n/2+1)² 不应该是m²-(n/2-1)²么?????
再答: 对,我搞错了 =[m+(n/2-1)][m-(n/2-1)]-(m-1)²+(n/2+1)² =m²-(n/2-1)²-(m²-2m+1)+(n/2+1)² =m²-n²/4+n-1-m²+2m-1+n²/4+n+1 =2n-1+2m
=m²+(n/2-1)²-(m²-2m+1)+(n/2+1)²
=m²+n²/4-n+1-m²+2m-1+n²/4+n+1
=n²/2+1+2m
再问: m²+(n/2-1)²-(m²-2m+1)+(n/2+1)² 不应该是m²-(n/2-1)²么?????
再答: 对,我搞错了 =[m+(n/2-1)][m-(n/2-1)]-(m-1)²+(n/2+1)² =m²-(n/2-1)²-(m²-2m+1)+(n/2+1)² =m²-n²/4+n-1-m²+2m-1+n²/4+n+1 =2n-1+2m
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