{|3m-m|/√2}^2+(√7)^2=(3m)^2 怎么算

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${|3m-m|/√2}^2+(√7)^2=(3m)^2 怎么算$

{|3m-m|/√2}^2+(√7)^2=(3m)^2
(2m)^2/2+7=9m^2
2m^2+7=9m^2
7m^2=7
m^2=1
m=±1
再问：如果是这样你在http://zhidao.baidu.com/question/364379847.html 不就算错了?

(m+3m+5m+...+2009m)-(2m+4m+...+2008m)怎么算 m-2m-3m+4m-5m-6m+7m.2004m=? {|3m-m|/√2}^2+(√7)^2=(3m)^2 怎么算 (m+3m+5m+7m+.+2009m)-(2m-4m-6m-.-2008m)=? (m+3m+5m.+2013m)-(2m+4m+6m+.+2012m)=? (m+3m+5m+...+2015m)-(2m+4m+6m+...+2014m)= (m+3m5m+7m+.2009m)-(2m+4m+6m.2008m) 已知m＞4,化简|m-4|+|7-2m|+|m×m-2m+1|-|m×m-2m-3| (m+3m+5m+7m+.+2011m)-(2m+4m+6m+.+2010m) 要说理由! m-2m-3m+4m-5m-6m+7m-8m-9m+.+2002m-2003m-2004m 化简求值:m^2-1/m+1-m√m^2-2m+1/m^2-m,其中m=2-√3 (m+3m+5m+.+2008m)-(2m+4m+6m+.+2009m)