求极限Sn=((1+1/n^2)^0.5-1)+((1+2/n^2)^0.5-1)+...+((1+n/n^2)^0.5
在数列{an}中,an=1/n(n+1)(n+2),求Sn的极限
求极限Sn=((1+1/n^2)^0.5-1)+((1+2/n^2)^0.5-1)+...+((1+n/n^2)^0.5
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Sn=n(n+2)(n+4)的分项等于1/6[n(n+2)(n+4)(n+5)-(n-1)n(n+2)(n+4)]吗?
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已知Sn=2+5n+8n^2+…+(3n-1)n^n-1(n∈N*)求Sn