(2/3)^x≤1/20 (已知:lg2=0.3010,lg3=0.4771)
(2/3)^x≤1/20 (已知:lg2=0.3010,lg3=0.4771)
已知lg2=0.3010,lg3=0.4771,lgx=-2+0.7781,则x=( )
已知lg2=0.3010,lg3=0.4771,计算:(1)lg9/2;(2)lg3.6;(3)lg根号6/2
lg2=0.3010 lg3=0.4771 lg15 =lg3+lg5 =lg3+1-lg2 =1.7781 中lg3+
1/(1+log3 2)+1/(1+log2 3)=lg3/(lg2+lg3)+lg2/(lg2+lg3)=1解释一下这
已知lg2=0.3010,lg3=0.4771 求 lg32=?lg3/2=?lg根号3/2=?
已知lg2=a,lg3=a,则lg2/3等于( )
数学:已知lg2=0.3010,lg3=0.4771,求lg(根号下)45
(lg3+2lg2-1)除以lg1.2=?
已知lg2=a,lg3=b求:(1)lg6= (2)log3;4= (3)log2;12= (4)lg3/2=
已知lg2=a,lg3=b,求下列各式的值 (1)lg6 (2)log3|4 (3)log2|12 (4)lg3/2
已知lg2=0.3010求lg3